Yes, I’m hoping our resident stove innovator and science whiz will contribute their thoughts.
From some research on the internet:
Propane has a boiling temperature of -43.6°F vs. butane at 28.4°F.
Butane can reach maximum temperatures of around 2,400 degrees Fahrenheit. The maximum temperature of propane is around 3,600 degrees Fahrenheit.
Total heating value after oxidation of propane is 19768 BTU/lb. and butane is 19494 BTU/lb. So energy per gram is almost the same. But it’s not just the BTU output that’s important, it’s the transfer rate. It involves BTU generation in the flame, as well as flame velocity.
Propane has a higher burning velocity. That means that even if the energy stored in a given volume of butane were slightly higher (it’s not), you’d get the energy out of the propane faster. Even more significant is the combustion ratio. Propane takes less volume of oxygen or air (mostly oxygen plus nitrogen) to burn. What that means is that for the energy in a given volume of butane, more oxygen is required to get it out. Those other gases, nitrogen and oxygen, are also at room temperatue when mixed with the fuel, and share in the energy release by the fuel to heat it to flame temp. That results in the stated amount of BTUs being released by that volume of fuel gas, but it’s diluted through a much larger total volume of flame gas, thus giving a lower flame temperature, especially when burned in air (remember all that excess nitrogen)
It’s the combination of higher flame temperature, and higher flame velocity, that allows propane to perform better