If ’70’ in the formula is a ‘reference temperature’ based upon the Farenheit scale, then ’20’ cannot arbitrarily be substituted to convert it to Celcius without taking into account the temperature conversion formula (°F – 32) x (5/9) = °C
Bob, we have:
z = x – (70-y)/2
z’ = 5/9(z – 32), x’ = 5/9(x-32), y’ = 5/9(y-32)
then
z’ = x’ – (21-y’)/2
If you check the algebra, you will find that for this particular formula, the equivalent formula in Centigrade units does just involve changing the 70 to 21. Everything else cancels.


