First off, thanks for the info. Here is where I get confused.
A fridge works by releasing pressurised gas. It stays colder when you insulate it. It doesn't work so well when you leave the door open
But this is assuming that the outside temperature is warmer then the inside temperature. Imagine you want the fridge to be 40*F and no lower so you set the temperature and close the door to insulate it. The outside temperature is 0*F and if you open the door or remove the insulation, the fridge will get colder inside because the outside air is colder then inside the fridge. You want to isolate it from this lower temperature (ie. canister cozy). Leaving the door open would only WARM the inside of the fridge if the temperature inside the fridge dropped lower then 0*F outside temperature, in which case you would open the door and actually warm the inside of the fridge with the 0*F outside temperature.
This is my logic for making a canister cozy. At warm temps, the cozy would do nothing because the canister would be colder then the outside air which means simply exposing the canister to this warmer air would be better then isolating it. But if I had the canister in my jacket and put the cozy on it to expose it to -5*F temps would it not benefit from the isolation?
I hope this is making sense. :)
So, let me try and sum up a question here.
At what temperature will it be beneficial to isolate the canister from the environment and what temperature will the environment warm an uninsulated canister?
Or.
I assume that since the fuel mixture will stop boiling at roughly 0*F that the act of burning the fuel does not create this temperature or else an insulated canister run at full would eventually stop working? What temperature is created by burning the fuel?
With both you guys from Australia, I'm going to have to wait until tomorrow morning to get an answer. ;)'
p.s. Rod, I'll start working on a canister shaped beer can.